Question

1-Dada as funções afim determine seu valor quando "x" recebe -2;-1;0;1;2:

a) f(x)= 2x+8

b)f(x)=5x+10

c)f(x)=10x+2

d)f(x)=2x+2

e)f(x)=10x+2

f)f(x)=3x+1

g)f(x)=2x+5

h)f(x)=9x+6

Answer 1

a) f(x)= 2x+8
f(-2)= 2.(-2)+8
f(-2)= -4+8
f(-2)= 4

f(-1)= 2.(-1)+8
f(-1)= -2+8
f(-1)= 6

f(0)= 2.0+8
f(0)= 8

f(1)= 2.1+8
f(1)= 10

f(2) = 2.2+8
f(2) = 12

b) f(x) = 5x+10
f(-2) = 5.(-2)+10
f(-2) = -10+10
f(-2) = 0

f(-1)= 5.(-1)+10
f(-1) = -5+10
f(-1) = 5

f(0)= 5.0+10
f(0)= 10

f(1)= 5.1+10
f(1)= 15

f(2)= 5.2+10
f(2)= 20

c) f(x)= 10x+2
f(-2)= 10.(-2)+2
f(-2)= -20+2
f(-2)= -18

f(-1)= 10.(-1)+2
f(-1)= -10+2
f(-1)= -8

f(0)= 10.0+2
f(0)= 2

f(1)= 10.1+2
f(1)= 12

f(2)= 10.2+2
f(2)= 22

d) f(x)= 2x+2
f(-2)= 2.(-2)+2
f(-2)= -4+2
f(-2)= -2

f(-1)= 2.(-1)+2
f(-1)= -2+2
f(-1)= 0

f(0)= 2.0+2
f(0)= 2

f(1)= 2.1+2
f(1)= 4

f(2)= 2.2+2
f(2)= 6

e) f(x)= 10x+2 <- Função afim igual à da letra c, logo os valores obtidos serão os mesmos!

f) f(x)= 3x+1
f(-2)= 3.(-2)+1
f(-2)= -6+1
f(-2)= -5

f(-1)= 3.(-1)+1
f(-1)= -3+1
f(-1)= -2

f(0)= 3.0+1
f(0)= 1

f(1)= 3.1+1
f(1)= 4

f(2)= 3.2+1
f(2)= 7

g) f(x)= 2x+5
f(-2)= 2.(-2)+5
f(-2)= -4+5
f(-2)= 1

f(-1)= 2.(-1)+5
f(-1)= -2+5
f(-1)= 3

f(0)= 2.0+5
f(0)= 5

f(1)= 2.1+5
f(1)= 7

f(2)= 2.2+5
f(2)= 9

h) f(x)= 9x+6
f(-2)= 9.(-2)+6
f(-2)= -18+6
f(-2)= -12

f(-1)= 9.(-1)+6
f(-1)= -9+6
f(-1)= -3

f(0)= 9.0+6
f(0)= 6

f(1)= 9.1+6
f(1)= 15

f(2)= 9.2+6
f(2)= 24