Question

1 Dada a função quadrática f(x) = -x2 - x + 2

a) Determine as raízes x'ex".​

Answer 1

Resposta:

-x²-x+2

a = -1 b= -1 c = 2

∆ = b²-4ac

∆= (-1)² - 4*(-1)*2

∆= 1+4*2

∆=9

X1 = -b+√∆/2*a

X1 = 1+√9/2*(-1)

X1 = 1+3/-2

X1 = 4/-2

X1 = -2

X2 = -b-√∆/2*a

X2 = 1-√9/-2

X2 = 1-3/-2

X2 = -2/-2

X2 = 1