1)Dada a função quadrática f(x) = 3x² – 2x + 4, calcule:
f(1) + f (3) - f ( 2)
f( 3/2)
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Resposta:
f(x) = 3x² – 2x + 4
f ( 1 ) = 3x^2 - 2x + 4
f ( 1 ) = 3 × ( 1 × 1 ) - 2 × 1 + 4
f ( 1 ) = ( 3 × 1 ) - 2 + 4
f ( 1 ) = 3 - 2 + 4
f ( 1 ) = 5
f ( 2 ) = 3x^2 - 2x + 4
f ( 2 ) = 3 × ( 2 × 2 ) - 2 ×2 + 4
f ( 2 ) = ( 3 × 4 ) - 4 + 4
f ( 2 ) = 12 - 4 + 4
f ( 2 ) = 12
f ( 3 ) = 3x^2 - 2x + 4
f ( 3 ) = 3 × ( 3 × 3 ) - 2 ×3 + 4
f ( 3 ) = ( 3 × 9 ) - 6 + 4
12f ( 3 ) = 27 - 6 + 4
f ( 3 ) = 19 + 4
f ( 3 ) = 23
f ( 3/2 ) = 3x^2 - 2x + 4 3/2 = 1,5
f ( 3/2 ) = 3 × ( 1,5 )^2 - 2 × 1,5 + 4
f ( 3/2 ) = 3 × ( 1,5 × 1,5 ) - 3 + 4
f ( 3/2 ) = 3 × 2,25 + 1
f ( 3/2 ) = 6,75 + 1
f ( 3/2 ) = 7,75
f(1) + f (3) - f (2)
5 + 23 - 12 = 16
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