Question

1) Dada a função f(x) = ax + b e sabendo-se que f(3) = 5 e f(-2) = -5 calcule f(1/2)

Answer 1

f(x) = ax + b
f(3)=a3+b
5=3a+b
b=5-3a

f(-2)=-2a+b
-5=-2a+(5-3a)=-2a+5-3a
-5-5=-5a
10=5a
a=2
b=5-3*2=5-6
b=-1

f(x)=2x-1
f(1/2)=2*(1/2)-1=1-1
f(1/2)=0