Question

1-Dada a função f( x ) = 3x – 9, com X Ꞓ R e Y Ꞓ R determine:

a)f ( - 1 )

b)f ( 0 )

c)f ( 3 )

d)f ( 1/3 )


2-Dada a função f( x ) = 2x + 1, calcule:

a)f ( 0 )

b)f ( -2 )

c)f ( 4 )

d)f ( 3 )

e)f ( -1 )

f)f ( 5 ) 

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Answer 1

Resposta:

1) a) f( x ) = 3x – 9

f(-1) = 3.(-1) - 9

f(-1) = - 3 - 9

f(-1) = -12

b) f( x ) = 3x – 9

f(0) = 3.0 - 9

f(0) = 0 - 9

f(0) = -9

c) f( x ) = 3x – 9

f(3) = 3.3 - 9

f(3) = 9 - 9

f(3) = 0

d) f( x ) = 3x – 9

f(1/3) = 3.1/3 - 9

f(1/3) = 3/3 - 9

f(1/3) = -8

2) a) f( x ) = 2x + 1

f(0) = 2.0 + 1

f(0) = 0 + 1

f(0) = 1

b) f( x ) = 2x + 1

f(-2) = 2.(-2) + 1

f(-2) = - 4 + 1

f(-2) = -3

c) f( x ) = 2x + 1

f(4) = 2.4 + 1

f(4) = 8 + 1

f(4) = 9

d) f( x ) = 2x + 1

f(3) = 2.3 + 1

f(3) = 6 + 1

f(3) = 7

e) f( x ) = 2x + 1

f(-1) = 2.(-1) + 1

f(-1) = -2 + 1

f(-1) = -1

f) f( x ) = 2x + 1

f(5) = 2.5 + 1

f(5) = 10 + 1

f(5) = 11

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