Question

1) Dada a função afim f(x) = 8x + 15, calcule:
a) f(2)=
b) f( 3)=
c) f(0) + f(3)=
d) f(5) - f(10)=​

Answer 1

) f(×)=8×+15

f(2)=8.2+15

f(2)=16+15

f(2)=31

B)

f(×)=8×+15

f(3)=8.3+15

f(3)=24+15

f(3)=39

C)

f(x)=8×+15

f(0)=8.0+15

f(0)=0+15

f(0)=15

f(x)=8×+15

f(3)=8.3+15

f(3)= 24+15

f(3)=39

15+39=54.

D)

f(×)=8×+15

f(5)=8.5+15

f(5)=40+15

f(5)=55

f(×)=8×+15

f(10)=8.10+15

f(10)=80+15

f(10)=95

55-95= -40

espero ter ajudado!