Question

1- Construa a matriz B=(b)y 3+3, tal que bij= (i+j)²

Answer 1

1)

B=(b)y 3+3,  tal que bij= (i+j)²

B = (b₁₁  b₁₂  b₁₃)

     (b₂₁ b₂₂ b₂₃)

     (b₃₁ b₃₂ b₃₃)

b₁₁ =  (i+j)² => (1+1)² => 2² => 4

b₁₂ =  (i+j)² => (1+2)² => 3² => 9

b₁₃ = (i+j)² => (1+3)² => 4² => 16

b₂₁ = (i+j)² => (2+1)² => 3² => 9

b₂₂ = (i+j)² => (2+2)² => 4² => 16

b₂₃ = (i+j)² => (2+3)² => 5² => 25

b₃₁ = (i+j)² => (3+1)² => 4² => 16

b₃₂ = (i+j)² => (3+2)² => 5² => 25

b₃₃ = (i+j)² => (3+3)² => 6² => 36

B = (4   9   16)

     (9  16  25)

     (16 25 36)

2) A = B

(x+y   2)      =      (12   9)

(9   y²+y)              (2  53)

x+y = 12

x = 12-y

y²+y = 2

y(y+1)=2

y'=2

y"=-1

p/ y=2

x = 12-y

x = 12 - 2

x = 10

p/ y =-1

x = 12-y

x = 12-(-1)

x = 13