Question

1. Considere a equação abaixo e, faça o que se pede:
x2 + 12x - 189 = 0
a) Identifique os coeficientes a, b ec.
b) Calcule o discriminante A= b2 - 4ac
c) Determine o valor de xie x2​

Answer 1

Equação do Segundo Grau

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• A) Coeficientes:

A = 1

B = 12

C = -189

• B) Discriminante:

$\boxed{\begin{array}{lr}\\\large \sf \Delta= b^{2} -4ac\\\\\large \sf \Delta= (12)^{2} -4\cdot1\cdot-189\\\\\large \sf \Delta=144-(-756)\\\\\large \sf\red{ \Delta=900}\\\:\end{array}}$

• Letra C) Valor de x1 e x2:

$\large\boxed{\begin{array}{l}\\ \sf x_{1}=\dfrac{-(+12)+\sqrt{900}}{2\cdot a}= \dfrac{-12+30}{2} =\boxed{\sf 9}\\ \\ \end{array}}$

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$\large\boxed{\begin{array}{l}\\ \sf x_{2}=\dfrac{-(+12)-\sqrt{900}}{2\cdot a}= \dfrac{-12-30}{2}=\boxed{\large \sf -21}\\ \\ \end{array}}$

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