Question

1)Considerando log 2 = 0,3010 e log 3 = 0,4771, calcule:
a)log 125

Answer 1

log 125 ==> log 5^3 ==> 3log5 ==> 3(log10/2) ==> 3log10 - 3log2

3.1  - 3.(0,3010) ==> 3 - 0,9030

2,0970