Question

1- considerando a figura, determine:

Answer 1

Teorema de Pitágoras:

$a^2=2^2+4^2~~\Rightarrow~~a^2=4+16~~\Rightarrow~~a^2=20$

$a=\sqrt{20}~~\Rightarrow~~a=3\sqrt{5}$.

b) $b^2=4^2+8^2~~\Rightarrow~~b^2=16+64~~\Rightarrow~~b^2=80$

$b=\sqrt{80}~~\Rightarrow~~b=4\sqrt{5}$.

c) $c^2=a^2+b^2~~\Rightarrow~~c^2=20+80~~\Rightarrow~~c^2=100$

$c=\sqrt{100}~~\Rightarrow~~c=10$.

d) Perímetro do trapézio MNPQ:

$MN+NP+PQ+QM=8+8+10+2=28$.

Answer 2

$x^{2} = 4 ^{2} + 2^{2} > x^{2} =16+4 > x^{2} =20 > x= \sqrt{20} > x= 4,4....$

medida A é 4,4....$x^{2} = 20+80 > x^{2} =100 > x= \sqrt{100}> x=10$

$x^{2} = 4^{2} + 8^{2}.> x^{2} = 16+64 .> x^{2} =80 > x= \sqrt{80}> x = 8,9....$

medida B é 8,9....

$x^{2} = 20+80 > x^{2} =100 > x= \sqrt{100}> x=10$

medida C é 10

2+4+4+8+10 = 28 

28 é o perimetro todo