Matemática, perguntado por kakazola0302, 1 ano atrás

1-calcuole
a) (-4)^3-3-10
b) 20+(-2)^4-25
c) -30+(-5)^4+50^2
d)150+(-7)^2-(-30)+10
e)(-9)^3-20-(-40)^2-6^2
f)(-3)^2-(-4)^2+(-5)^2-15
g(-3)^2+(-3)^4+(-2)^4+(-2)^5+(-2)^5

Soluções para a tarefa

Respondido por valterbl
0

Oi...

a)(-4)^3-3-10=-64-3-10=-77\\\\b)20+(-2)^4-25=20-12-25=11\\\\c)-30+(-5)^4+50^2=-30+625+2500=3095\\\\d)150+(-7)^2-(-30)+10=150+49+30+10=239\\\\e)(-9)^3-20-(-40)^2-6^2=-729-20-1600-36=-2385\\\\f)(-3)^2-(-4)^2+(-5)^2-15=9-16+25-15=3\\\\g)(-3)^2+(-3)^4+(-2)^4+(-2)^5+(-2)^5=\\\\\\9 +81+16+2.(-2)^5\\\\9+81+16+2.(-2^5)\\\\9+81+16-2^6\\\\9+81+16-64\\\\42

Espero ter ajudado

Perguntas interessantes