Matemática, perguntado por minesplay10, 8 meses atrás

1) Calcule x nas figuras abaixo:




por favor me ajudem urgente​

Anexos:

Soluções para a tarefa

Respondido por CyberKirito
1

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\tt a)~\sf x^2+(3\sqrt{2})^2=(3\sqrt{11})^2\\\sf x^2+18=99\\\sf x^2=99-18\\\sf x^2=81\\\sf x=\sqrt{81}\\\huge\boxed{\boxed{\boxed{\boxed{\sf x=9\checkmark}}}}

\tt b)~\sf(3x)^2=(2x)^2+(5\sqrt{3})^2\\\sf 9x^2=4x^2+45\\\sf 9x^2-4x^2=45\\\sf 5x^2=45\\\sf x^2=\dfrac{45}{5}\\\sf x^2=9\\\sf x=\sqrt{9}\\\huge\boxed{\boxed{\boxed{\boxed{\boxed{\sf x=3\checkmark}}}}}

\tt c)~\sf(2x)^2=(3\sqrt{3})^2+x^2\\\sf 4x^2=27+x^2\\\sf 4x-x^2=27\\\sf3x^2=27\\\sf x^2=\dfrac{27}{3}\\\sf x^2=9\\\sf x=\sqrt{9}\\\huge\boxed{\boxed{\boxed{\boxed{\sf x=3\checkmark}}}}

\tt d)~\sf (x+1)^2=x^2+3^2\\\sf \diagup\!\!\!x^2+2x+1=\diagup\!\!\!x^2+9\\\sf 2x+1=9\\\sf 2x=9-1\\\sf 2x=8\\\sf x=\dfrac{8}{2}\\\huge\boxed{\boxed{\boxed{\boxed{\boxed{\sf x=4\checkmark}}}}}

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