1)calcule pelo processo da decomposição simultânea o MMC de: a)12e15 c)6e20 12,15 6,20 b)30e48 30,48 e)e6e20 30, 6,20 MMC (12,15)= MMC (30,48)= MMC (0p6,20)= d) 60 e 24 e 45 e) 36 f )18 e 27 MMC (60,24)= MMC (36,45)= MMC (18,27)= 2) continue calculando :a) MMC (12, 20 , 40 = b) MMC ( 24 , 36 , 54 = 12 , 30 40
34 , 36 , 54 6, 15 , 20 c) MMC ( 18, 20, 45)= d) MMC ( 40 , 45, 72 )=
Me AJUDA!
Soluções para a tarefa
Resolvendo o que entendi, pois o seu enunciado ficou muito confuso...
a) MMC (12,15)= 60
12, 15 | 2
6, 15 | 2
3, 15 | 3
1, 5 | 5
1, 1 | 1
MMC = 2 . 2 . 3 . 5 = 60
b) MMC (30,48)= 240
30, 48 | 2
15, 24 | 2
15, 12 | 2
15, 6 | 2
15, 3 | 3
5, 1 | 5
1, 1 | 1
MMC = 2 . 2 . 2 . 2 . 3 . 5 = 240
c) MMC (6,20)= 60
6, 20 | 2
3, 10 | 2
3, 5 | 3
1, 5 | 5
1, 1 | 1
MMC = 2 . 2 . 3 . 5 = 60
d) MMC(60,24)= 120
60, 24 | 2
30, 12 | 2
15, 6 | 2
15, 3 | 3
5, 1 | 5
1, 1 | 1
MMC = 2 . 2 . 2 . 3 . 5 = 120
e) MMC (36,45)= 180
36, 45 | 2
18, 45 | 2
9, 45 | 3
3, 15 | 3
1, 5 | 5
1, 1 | 1
MMC = 2 . 2 . 3 . 3 . 5 = 180
f) MMC (18,27)= 54
18, 27 | 2
9, 27 | 3
3, 9 | 3
1, 3 | 3
1, 1 | 1
MMC = 2 . 3 . 3 . 3 = 54
2) continue calculando :
a) MMC (12, 20 , 40) = 120
12, 20, 40 | 2
6, 10, 20 | 2
3, 5, 10 | 2
3, 5, 5 | 3
1, 5, 5 | 5
1, 1, 1 | 1
MMC = 2 . 2 . 2 . 3 . 5 = 120
b) MMC ( 24 , 36 , 54) = 216
24, 36, 54 | 2
12, 18, 27 | 2
6, 9, 27 | 2
3, 9, 27 | 3
1, 3, 9 | 3
1, 1, 3 | 3
1, 1, 1 | 1
MMC = 2 . 2 . 2 . 3 . 3 . 3 = 216
c) MMC ( 18, 20, 45)= 180
18, 20, 45 | 2
9, 10, 45 | 2
9, 5, 45 | 3
3, 5, 15 | 3
1, 5, 5 | 5
1, 1, 1 | 1
MMC = 2 . 2 . 3 . 3 . 5 = 180
d) MMC ( 40 , 45, 72 )= 360
40, 45, 72 | 2
20, 45, 36 | 2
10, 45, 18 | 2
5, 45, 9 | 3
5, 15, 3 | 3
5, 5, 1 | 5
1, 1, 1 | 1
MMC = 2 . 2 . 2 . 3 . 3 . 5 = 360