Question

1-calcule os monômios H) (3,2x³).(0,7x³)= i) (4a³b).(3b)= J) (⅔xy³).(¼x².y²)= K) (12x²):(4x²)= L ) (-3y).(4y²)= M) -12a+9a+5a= N) X²/6 -2x²/9+x²= O) 8,6x²-4,1x²= P) (X/5.3x)= Q) (-9x²y).(-2xy²)= R) (14a³b²)=(2ab) = galera eu quero os cálculos com as respostasde cada

Answer 1

H) $(3,2x^3)(0,7x^3)=3,2\cdot0,7x^6=2,24x^6$

I) $(4a^3b)(3b)=4\cdot3\cdota^3b^2=12a^3b^2$

J) $(\frac{2}{3}xy^3)(\frac{1}{4}x^2y^2)=\frac{2\cdot1}{3\cdot4}x^3y^5=\frac{1}{6}x^3y^5$

K) $\dfrac{(12x^2)}{(4x^2)}=\dfrac{12}{4}\dfrac{x^2}{x^2}=3$

L) $(-3y)(4y)^2=(-3)4y^3=-12y^3$.

M) $-12a+9a+5a=(-12+9+5)a=(-12+14)a=2a$

O) $8,6x^2-4,1x^2=(8,6-4,1)x^2=4,5x^2$.

P) $\dfrac{x}{5}\cdot3x=\dfrac{3x^2}{5}$

Q)  $(-9x^2y)(-2xy^2)=(-9)(-2)x^3y^3=18x^3y^3$

R) $(14a^3b^2)(2ab)=14\cdot2a^4b^3=28a^4b^3$