Question

1) Calcule os logaritmos e expresse os cálculos. Dados: log2=0,310 ; log3=0,477 a) Log6= b) log48= c) log120=

Answer 1

a) Log 6 = log 2.3 = log 2 + log 3 = 0,310 + 0,477 = 0,787
b) Log 48 = log 2.2.2.2.3 = log 2.2.2.2 + log 3 = 4.log 2 + log 3 = 4.0,310 + 0,477 = 1,717
c) Log 120 = log 12.10 = log 3.2.2 + log 10 = log 3 + 2.log 2 + 1 = 0,477 + 2.0,310 + 1 = 2,097
Lembrando: log 10= 1; log x^n= n.log x; log x.y= log x + log y; log x/y= log x - log y; log 10^n= n