Question

1) Calcule o valor de cada expressão:
a) 2-(-2/3-1/4)
b) (-1+1/2)-(-1/6+2/3)
c) (-3/4+5/2-1/3)-(1/2+1)
d) (1/3+1/2)-(-3/4+5/6)
e) (-1/6+2/3)-(1/2-1)
f) 2-[3/8-(1/4-1/2)]
g) 3-[-1/2-(0,1+1/4)]
h) -{-[-(-1/3-1-3/4)]}

por favor me ajudem!!!!!

Answer 1

Resposta:

Resolva primeiro as operações que estão dentro de parênteses

$a)\\ \\2-(-\frac{2}{3}-\frac{1}{4})\\ \\mmc=12\\\\2-(-\frac{8-3}{12})=2-(-\frac{5}{12})=2+\frac{5}{12}=\frac{24+5}{12}=\frac{29}{12}\\ \\b)\\ \\(-1+\frac{1}{2})-(-\frac{1}{6}+\frac{2}{3})=(\frac{-2+3}{2})-(\frac{-1+4}{6})=\frac{1}{2}-\frac{3}{6}=\frac{3-3}{6}=\frac{0}{6}=0\\ \\c)\\ \\(-\frac{3}{4}+\frac{5}{2}-\frac{1}{3})-(\frac{1}{2}+1)=(\frac{-9+30-4}{12})-(\frac{1+2}{2})=\frac{25}{12}-\frac{3}{2}=\frac{25-18}{12}=\frac{7}{12}$

$d)\\ \\(\frac{1}{3}+\frac{1}{2})-(-\frac{3}{4}+\frac{5}{6})=(\frac{2+3}{6})-(\frac{-9+10}{12})=\frac{5}{6}-\frac{1}{12}=\frac{10-1}{12}=\frac{9}{12}=\frac{3}{4}\\ \\e)\\ \\(-\frac{1}{6}+\frac{2}{3})-(\frac{1}{2}-1)=(\frac{-1+4}{6})-(\frac{1-2}{2})=\frac{3}{6}-(-\frac{1}{2})=\\ \\\frac{3}{6}+\frac{1}{2}=\frac{3+3}{6}=\frac{6}{6}=1\\ \\f)\\ \\2-[\frac{3}{8}-(\frac{1}{4}-\frac{1}{2})]=2-[\frac{3}{8}-(\frac{1-2}{4})]=2-[\frac{3}{8}-(-\frac{1}{4})]=\\ \\2-(\frac{3}{8}+\frac{1}{4})=2-(\frac{3+2}{8})=$

$2-\frac{5}{8}=\frac{16-5}{8}=\frac{11}{8}$

$g)\\ \\3-[-\frac{1}{2}-(0,1+\frac{1}{4})]=3-[-\frac{1}{2}-(\frac{1}{10}+\frac{1}{4})]=\\ \\3-[-\frac{1}{2}-(\frac{2+5}{20})]=3-(-\frac{1}{2}-\frac{7}{20})=3-(\frac{-10-7}{20})=3-(-\frac{17}{20})=\\ \\3+\frac{17}{20}=\frac{60+17}{20}=\frac{77}{20}\\\\\\h)\\ \\-[-(-[-\frac{1}{3}-1-\frac{3}{4}])]=\frac{-4-12-9}{12}=-[-(-[-\frac{25}{12}])]=+\frac{25}{12}$