Question

1) Calcule o valor das expressões numéricas abaixo:

a) 32: (4 x 2) + (32: 4) x 2 =

b) 32: (4 x 2 + 32: 4) x 2 =

c) 32: [(4 x 2 + 32: 4) x 2] =

d) 400 – {10 – [30: (30 – 0: 17)] – 1} =

e) 27 + {14 + 3 x [100: (18 – 4 x 2) + 7]}: 13 =

f) [(16 – 22 + 1) – (22 + 10)] – 0 + 30 =

g) 1 + {- 2 + [3 + (- 4 + 5 – 6) + 7 – 8 } =

h) (– 7 – 2) + (– 7 + 2) + (+ 7 – 2 ) =

i) 23 – {1 + [5 – (+ 3 – 2 + 1)]}=

j) 32 + {+ 48 – [+ 34 – (–10 + 18 – 4)]}=

k) (8 : 2) . 4 + {[(3² - 2³) . 2⁴ - 5⁰] . 4¹}=

l) (3² - 2³) . 3³ - 2³ + 2² . 4² =

m) ( 2⁵ - 3³) . (2² - 2 ) =

n) [2 . (10 - 4² : 2) + 6²] : ( 2³ - 2²) =

o) (18 – 4 . 2) . 3 + 2⁴ . 3 - 3² . ( 5 – 2) =

p) 4² . [2⁴ : ( 10 – 2 + 8 ) ] + 2⁰ =

q) [( 4² + 2 . 3²) + ( 16 : 8)² - 35]² + 1¹⁰ - 10⁰ =​

Answer 1

Resposta:

Explicação passo-a-passo:

a) 32:8 + 8x2

4+16 =20

b) 32: (8+8) x2

32:16x2

2x2= 4

c) 32: ((8+8)x2))

32:(16x2)

32:32=1

d) 400- (10 - (30: (30)-1)

400-(10-(1-1))

400-10=390

e) 27 + (14+3 x (100:(18-8)+7)):13

27+(14+3x(100:10+7)):13

27+(14+ 3 x (17)):13

27 + (14 + 51):13

27+65:13

27+ 5 =32

f) ( -5) -(32)+30

-5-32+30

-37+30 = -7

g)

1+(-2+(3+(-5)-1)

1+( -2+ ( 3-5-1)

1+(-2-3)

1-5= -4

h)

-9-5+5= -9

i) 23-(1+(5-(2))

23-(1+3)

23-4= 19

j)

32+(48 -( 34 -(4))

32+(48 - 30)

32+18 = 50

k)

4.4 +( (9-8). 16 -1) .4)

16 + (15).4

16+60= 76

l)  (9-8). 27-8+4 x16

27-8+ 64 = 83

m) 32- 27 . (4-2)

5.2= 10

n) (2.(10-16:2)+36): (8-4)

(2.(10-8)+36):4

40:4 =10

o)

(18-8).3+ 16.3-9.3

30+48-27= 51

p)

16.(16:(16))+1

16.1+1

16+1=17

q)

((16+2x9) + (2)^2 -35)^2+1-1

(16+18+4-35)^2

(3)^2 = 9