Question

1. Calcule o limite.
a) Lim X² - 2X + 8 =
-> -2

Answer 1

$\lim_{x \to \ -2} x^{2} -2x +8$

$\lim_{x \to \ -2} (-2)^{2} -2.(-2) +8$

$\lim_{x \to \ -2} 4 +4 +8$

$\lim_{x \to \ -2} 16$

$\boxed {\lim_{x \to \ -2} x^{2} -2x +8 = 16}$