Question

1)calcule,indicando o resultado sem radical.
a)√3.√12=
b)3√2.3√4
c)5√8.5√4
d)√11.√11
e)√2.√50
f)√8.√0,5
g)√0,1.√10
h)√0,5.√5.√10​

Answer 1

$\sqrt{3} \times \sqrt{12} = \sqrt{36} = 6$

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$3 \sqrt{2} \times 3 \sqrt{4} \\ 9 \sqrt{8} = 9 \times 2 \sqrt{2} = 18 \sqrt{2} = 18 \times {2}^{ \frac{1}{2} }$

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$5 \sqrt{8} \times 5 \sqrt{4} \\ 25 \sqrt{32} = 25 \times 4 \sqrt{2} = 100 \sqrt{2} = 100 {2}^{ \frac{1}{2} }$

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$\sqrt{11} \times \sqrt{11} = \sqrt{121} = 11$

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$\sqrt{2} \times \sqrt{50} = \sqrt{100} = 10$

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$\sqrt{8} \times \sqrt{0.5} = \sqrt{4} = 2$

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$\sqrt{0.1} \times \sqrt{10} = \sqrt{1} = 1$

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$\sqrt{0.5} \times \sqrt{5} \times \sqrt{10} = \sqrt{25} = 5$