Question

1.calcule as somas abaixo, simplificando o resultado que possível:

a) 4/3+1/3=

b) 2/5+3+4=

c) 1/2+2/3=

d) 4/7+1/5=

e) 1/2+1/3+1/6=

2. Efetue as subtrações abaixo, simplificando resultado quando possível:

a) 3/2-2/3=

b) 4/6-1/3=

c) 4/5-3/4=

d) 4/7-2/5=

e) 1/2-1/3-1/6=

por favor me ajude pf​


quer me ajudar eu dou 50 ponto eu juro por Deus

Answer 1

1)

a) 4/3+1/3=

$\frac{4}{3} + \frac{1}{3} = \frac{4 + 1}{3} = \frac{5}{3}$

b) 2/5+3+4=

$\frac{2}{5} + 3 + 4 = \\ \frac{2}{5} + 7 = \\ \frac{2}{5} + \frac{7}{1} = \\ \frac{2 + (7 \times 5)}{5} = \\ \frac{2 + 35}{5} = \frac{37}{5}$

c) 1/2+2/3=

$\frac{1}{2} + \frac{2}{3} = \frac{(1 \times 3) + (2 \times 2)}{6} = \frac{3 + 4}{6} = \frac{7}{6}$

d) 4/7+1/5=

$\frac{4}{7} + \frac{1}{5} = \frac{(4 \times 5) + (1 \times 7)}{35} = \frac{20 + 7}{35} = \frac{27}{35}$

e) 1/2+1/3+1/6=

$\frac{1}{2} + \frac{1}{3} + \frac{1}{6} = \\ \frac{(1 \times 3) + (1 \times 2)}{6} + \frac{1}{6} = \\ \frac{3 + 2}{6} + \frac{1}{6} = \\ \frac{5}{6} + \frac{1}{6} = \frac{5 + 1}{6} = \frac{6}{6} = 1$

2.

a) 3/2-2/3=

$\frac{3}{2} - \frac{2}{3} = \frac{(3 \times 2) - (2 \times 3)}{6} = \frac{6 - 6}{6} = \frac{0}{6} = 0$

b) 4/6-1/3=

$\frac{4}{6} - \frac{1}{3} = \frac{(3 \times 4) - (1 \times 6)}{18} = \frac{12 - 6}{18} = \frac{6}{18} = \frac{1}{3}$

c) 4/5-3/4=

$\frac{4}{5} - \frac{3}{4} = \frac{(4 \times 4) - (5 \times 3)}{20} = \frac{12 - 15}{20} = - \frac{3}{20}$

d) 4/7-2/5=

$\frac{4}{7} - \frac{2}{5} = \frac{(4 \times 5) - (2 \times 7)}{35} = \frac{20 - 14}{35} = \frac{6}{35}$

e) 1/2-1/3-1/6=

$\frac{1}{2} - \frac{1}{3} - \frac{1}{6} = \\ \frac{(3 \times 1) - (2 \times 1)}{6} - \frac{1}{6} = \\ \frac{3 - 2}{6} - \frac{1}{6} = \\ \frac{1}{6} - \frac{1}{6} = \frac{0}{6} = 0$

Espero que isso tenha ajudado vc