Question

1) calcule as potências:
a) (4a/3)³
b) (a-1/3a)²
c) (2x/x-3)elevado a 0
d) (x-y/xy)elevado a -¹

Answer 1

Explicação passo-a-passo:

$a) (\frac{4a}{3})^3=\frac{64a^3}{27} \\\\b) (\frac{a-1}{3a})^2= \frac{a^2-2a+1}{9a^2}\\\\c) (\frac{2x}{x-3})^0=1\\\\d) (\frac{x-y}{xy})^{-1}=\frac{xy}{x-y}$

- Bons estudos :)