Question

1-Calcule as pontecias:

a)(2/7)^0


b)(2/7)¹

c)(0,3)²

d)(-2,1)²

e)(-3/5)²

f)(-3/5)³

g)(-0,4)³

Answer 1

a)(2/7)^0 =1

b)(2/7)^1=0,285

c)(0,3)²=0,09

d)(-2,1)²=4,41

e)(-3/5)² =0,36

f)(-3/5)³ = - 0,216

g)(-0,4)³= - 0,064

Um abraço.