Question

1) Calcule a soma: a)17x3 + 20x3 = b)2ax2 + 10b-6ax2 - 8b = c)-4xy + 6xy - 5xy = d)5b3 +7c3 + 6b3-2c3 =​

Answer 1

Resposta:

$17x^2+20x^3\\\\\mathrm{Aplicar\:as\:propriedades\:dos\:expoentes}:\quad \:a^{b+c}=a^ba^c\\\\x^3=xx^2\\\\20xx^2+17x^2\\\\\mathrm{Fatorar\:o\:termo\:comum\:}x^2\\\\X^2\left(20X+17\right)\\\\ = 37x^3\\\\\\\\2ax^2+10b-6ax^2-8b\\\\2ax^2-6ax^2+10b-8b\\\\-4ax^2+10b-8b\\\\-4ax^2+2b\\\\\\\\-4xy + 6xy - 5xy\\\\Apenas \ somar \\\\6-5 = 1-4= 3\\\\3xy\\\\\\\\\mathrm{Somar\:elementos\:similares:}\:5b^3+6b^3=11b^3\\\\11b^3-2c^3$

Answer 2

Oie, tudo bom?

a)

$= 17x {}^{3} + 20x {}^{3} \\ = (17 + 20)x {}^{3} \\ \boxed{ = 37x {}^{3} }$

b)

$= 2ax {}^{2} + 10b - 6ax {}^{2} - 8b \\ = (2 - 6)ax {}^{2} + (10 - 8)b \\ \boxed{ = - 4ax {}^{2} + 2b}$

c)

$= - 4xy + 6xy - 5xy \\ = ( - 4 + 6 - 5)xy \\ \boxed{ = - 3xy}$

d)

$= 5b {}^{3} + 7c {}^{3} + 6b {}^{3} - 2c {}^{3} \\ = (5 + 6)b {}^{3} + (7 - 2)c {}^{3} \\ \boxed{ = 11b {}^{3} + 5c {}^{3} }$

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