Question

1-Calcule a raiz ou zero das funções:

f(x) = 3(2x + 12) + 3(x - 8)
f(x) = -2(x +6) + 3(5x +8)
f(x) = -2(x + 9) - 9(3-2x)
f(x) = 3(2x -12) + 5(1 +2x)
h(x) = -5(2 +2x) - 7(x + 5)
g(x) = -6(x +1) + 4(2 -3x)

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Answer 1

Resposta:

f(x) = 3(2x + 12) + 3(x - 8)

0 = 6x + 36 + 3x - 24

0 = 9x + 12

-9x = 12

-9x ÷ (-9) = 12 ÷ (-9)

x = (-12/9) ÷3

x = (-4/3)

f(x) = -2(x +6) + 3(5x +8)

0 = -2x -12 + 15x + 24

0 = 13x + 12

-13x ÷(-13) = 12 ÷ (-13)

x = (-12/13)

f(x) = -2(x + 9) - 9(3-2x)

0 = -2x - 18 - 27 + 18x

0 = 16x - 45

-16x = -45

-16x ÷ (-16) = -45 ÷ (-16)

x = (45/16)

f(x) = 3(2x -12) + 5(1 +2x)

0 = 6x - 36 + 5 + 10x

0 = 16x - 31

-16x = -31

-16x ÷ (-16) = -31 ÷ (-16)

x = (31/16)

h(x) = -5(2 +2x) - 7(x + 5)

0 = -10 - 10x - 7x - 35

0 = -17x - 45

17x = -45

17x ÷ (17) = -45 ÷ (17)

x = (-45/17)

g(x) = -6(x +1) + 4(2 -3x)

0 = -6x - 6 + 8 - 12x

0 = -18x + 2

18x = 2

18x ÷ (18) = 2 ÷ (18)

x = (2/18) ÷ 2

x = (1/9)