Question

1)calcule a medida x dos triangualos a seguir urgente​

Answer 1

Resposta:

1)

a)

$\sin(30 {}^{o} ) = \frac{x}{5} \\ \\ \frac{1}{2} = \frac{x}{5} \\ \\ 2x = 5 \\ \\ x = \frac{5}{2}$

b)

Lei dos senos

$\frac{x}{ \sin(120 {}^{o} ) } = \frac{100}{ \sin(45 {}^{o} ) } \\ \\ \frac{x}{ \frac{ \sqrt{3} }{2} } = \frac{100}{ \frac{ \sqrt{2} }{2} } \\ \\ x \times \frac{ \sqrt{2} }{2} = 100 \times \frac{ \sqrt{3} }{2} \\ \\ x \sqrt{2} = 100 \sqrt{3} \\ \\ x = \frac{100 \sqrt{3} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ \\ x = \frac{100 \sqrt{6} }{ \sqrt{4} } \\ \\ x = \frac{100 \sqrt{6} }{2} \\ \\ x = 50 \sqrt{6} \: \: \: m$

Bons Estudos!