Question

1- A soma das raízes da equação a) -1. b) -2. c) -3. d) -4. (x ^ 2 + 3x)/6 = 2/3 ​

Answer 1

$\large\boxed{\begin{array}{l}\sf A~soma~das~ra\acute izes~da~equac_{\!\!,}\tilde ao~ax^2+bx+c=0\\\sf \acute e~dada~por~s=-\dfrac{b}{a}\\\sf\dfrac{x^2+3x}{6}=\dfrac{2}{3}\\\sf 3\cdot(x^2+3x)=6\cdot2\\\sf 3x^2+9x=12\\\sf 3x^2+9x-12=0\div3\\\sf x^2+3x-4=0\\\sf a=1~~b=3~~c=-4\\\sf s=-\dfrac{b}{a}\\\\\sf s=-\dfrac{3}{1}\\\\\sf s=-3\\\huge\boxed{\boxed{\boxed{\boxed{\sf\maltese~alternativa~c}}}}\end{array}}$