Question

1/8* (log7 10)*(log 49)

Answer 1

$(\frac{1}{8}).(log_710).(log49)=\\\\ (\frac{1}{8}).(log_710).(log7^2)=\\\\ (\frac{1}{8}).(log_710).(2.log7)=\\\\ (\frac{2}{8}).(log_710).(log7)=\\\\ (\frac{1}{4}).(log_710).(\frac{log_77}{log_710})=\\\\ (\frac{1}{4}).1=\frac{1}{4}$