Question

1)8.(2x-1)=6-(5x-2)-10

2)y-[y-(2-y)-1]+4=-(-3-y)

3)2.(x-2)-3.(1-x)=20-(x-4)

Answer 1

 1)  8.(2x-1)=6-(5x-2)-10 ==> 16x - 8=6 - 5x + 2 - 10

16X + 5X = + 2 - 10 + 6 + 8  ==> 21x = 6 ==> x = 6/21 ou x = 2/7
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2) y-[y-(2-y)-1]+4=-(-3-y) ==>  y - [ y - 2 +  y - 1] + 4 = 3 + y

 y - y + 2 -  y + 1 + 4 = 3 + y ==> - y - y = 3 - 2 - 1 - 4 ==> - 2y = - 4(-1)

2y = 4 ==> y = 2
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3) 2.(x-2)-3.(1-x)=20-(x-4) ==> 2x - 4 - 3 + 3x = 20 - x + 4 

2x + 3x + x  = 20 + 4 + 4 + 3 ==> 6x = 31 ==> x = 31/6