Question

1/4x²+5/4x-6=0 com a fórmula de baskara ?

Answer 1

Olá, boa noite ☺

Resolução:

$\\ \\ \frac{1}{4}x^2+ \frac{5}{4}x- \frac{6}{1} =0 \\ \\ \frac{(x^2+5x-24)}{4} =0 \\ \\ \texttt{Elimina\ o \ denominador \ 4.} \\ \\ x^2+5x-24=0 \\ \\ \texttt{ Coeficientes:} \\ \\ a=1 \\ b=5 \\ c=-24 \\ \\ \Delta= b^{2}-4.a.c \\ \Delta= 5^{2} -4.1.(-24) \\ \Delta=25+96 \\ \Delta=121$

$\ \texttt{ Valores \ de \ x:} \\ \\ x= \frac{-b\pm \sqrt{\Delta} }{2.a} \\ \\ x= \frac{-5\pm \sqrt{121} }{2.1} \\ \\ x= \frac{-5\pm11}{2} \\ \\ x'= \frac{-5+11}{2} = \frac{6}{2} =3 \\ \\ x''= \frac{-5-11}{2} = \frac{-16}{2} =-8$

Bons estudos :)