Question

1/4 dividido por 3/2 mais 1/4 elevado a 2 vzes raiz de 64/9

Answer 1

$\frac{ \frac{1}{4}}{ \frac{3}{2}} + (\frac{1}{4})^{2( \sqrt{ \frac{64}{9}})}$

Resolver primeiro raiz e expoente:

$\sqrt{64/9} = \frac{ \sqrt{64}}{ \sqrt{9}} = \frac{8}{3}$

$2. \frac{8}{3} = \frac{16}{3}$

$\frac{1}{4}^{16/3} = \sqrt[3]{(\frac{1}{4})^{16}} =[tex] \frac{1}{4}. \frac{2}{3} + 4^{ \frac{-16}{3}} = \frac{1}{6} + 4^{ \frac{-16}{3}}$  [/tex]