Matemática, perguntado por juliaxavier9, 11 meses atrás

(-1)-4*[(1/3-2)-2/(-1/5+0,4)*2]-0,8/0,625)-1

Soluções para a tarefa

Respondido por ShinyComet
1

    (-1)-4\times[\;(\frac{1}{3}-2)-\frac{2}{-\frac{1}{5}+0,4}\times2\;]-\frac{0,8}{0,625}-1=

=-1-4\times[\;(\frac{1}{3}-\frac{2\times3}{3})-\frac{2\times2}{-\frac{1}{5}+\frac{4}{10}}\;]-\frac{0,8\times1000}{0,625\times1000}-1=

=-1-4\times[\;(\frac{1}{3}-\frac{6}{3})-\frac{4}{-\frac{1}{5}+\frac{2}{5}}\;]-\frac{800}{625}-1=

=-1-4\times(-\frac{5}{3}-\frac{4}{\frac{1}{5}})-\frac{32}{25}-1=

=-1-4\times(-\frac{5}{3}-\frac{4\times5}{1})-\frac{32}{25}-1=

=-1-4\times(-\frac{5}{3}-\frac{20}{1})-\frac{32}{25}-1=

=-1-4\times(-\frac{5}{3}-\frac{20\times3}{3})-\frac{32}{25}-1=

=-1-4\times(-\frac{5}{3}-\frac{60}{3})-\frac{32}{25}-1=

=-1-4\times(-\frac{65}{3})-\frac{32}{25}-1=

=-1+\frac{260}{3}-\frac{32}{25}-1=

=-\frac{75}{75}+\frac{260\times25}{3\times25}-\frac{32\times3}{25\times3}-\frac{75}{75}=

=-\frac{75}{75}+\frac{6500}{75}-\frac{96}{75}-\frac{75}{75}=

=\frac{6425}{75}-\frac{96}{75}-\frac{75}{75}=

=\frac{6329}{75}-\frac{75}{75}=

=\frac{6254}{75}

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