(1/3)^x+3 = [tex] \sqrt[6]{243
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Olá, tudo bem?
![\left(\dfrac{1}{3}\right)^{x+3}= \sqrt[6]{243}\to 3^{(-x-3)}=3^{\frac5 6}\to\\\\-x-3=\dfrac{5}{6}\to -x=\dfrac{5}{6}+\dfrac{18}{6}\to\boxed{x=-\dfrac{23}{6}}\,\,\text{resposta final}](https://tex.z-dn.net/?f=%5Cleft%28%5Cdfrac%7B1%7D%7B3%7D%5Cright%29%5E%7Bx%2B3%7D%3D+%5Csqrt%5B6%5D%7B243%7D%5Cto+3%5E%7B%28-x-3%29%7D%3D3%5E%7B%5Cfrac5+6%7D%5Cto%5C%5C%5C%5C-x-3%3D%5Cdfrac%7B5%7D%7B6%7D%5Cto+-x%3D%5Cdfrac%7B5%7D%7B6%7D%2B%5Cdfrac%7B18%7D%7B6%7D%5Cto%5Cboxed%7Bx%3D-%5Cdfrac%7B23%7D%7B6%7D%7D%5C%2C%5C%2C%5Ctext%7Bresposta+final%7D "\left(\dfrac{1}{3}\right)^{x+3}= \sqrt[6]{243}\to 3^{(-x-3)}=3^{\frac5 6}\to\\\\-x-3=\dfrac{5}{6}\to -x=\dfrac{5}{6}+\dfrac{18}{6}\to\boxed{x=-\dfrac{23}{6}}\,\,\text{resposta final}")
É isso!! :-)
É isso!! :-)
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