Matemática, perguntado por lordfernand, 11 meses atrás

{1/3+[5-(1/5+1/4)-(3-2 1/2)]}+(4 1/2-3)​

Soluções para a tarefa

Respondido por Justdoit
1

Resposta:

5\frac{53}{60}

Explicação passo-a-passo:

\left\{\frac{1}{3}+\left[5-\left(\frac{1}{5}+\frac{1}{4}\right)-\left(3-2\frac{1}{2}\right)\right]\right\}+\left(4\frac{1}{2}-3\right)\\\\=\left\{\frac{1}{3}+\left[5-\left(\frac{1}{5}+\frac{1}{4}\right)-\left(3-\frac{5}{2}\right)\right]\right\}+\left(4\frac{1}{2}-3\right)\\\\=\left\{\frac{1}{3}+\left[5-\left(\frac{1}{5}+\frac{1}{4}\right)-\left(3-\frac{5}{2}\right)\right]\right\}+\left(\frac{9}{2}-3\right)\\\\

=\frac{1}{3}+5-\left(\frac{1}{5}+\frac{1}{4}\right)-\left(3-\frac{5}{2}\right)+\frac{9}{2}-3\\\\=\frac{1}{3}+5-\frac{9}{20}-\left(-\frac{5}{2}+3\right)+\frac{9}{2}-3\\\\=\frac{1}{3}+5-\frac{9}{20}-\frac{1}{2}+\frac{9}{2}-3\\\\=\frac{1}{3}-\frac{1}{2}+\frac{9}{2}-\frac{9}{20}+5-3\\\\=\frac{1}{3}+4-\frac{9}{20}+5-3\\\\=6+\frac{1}{3}-\frac{9}{20}\\\\=\frac{6}{1}+\frac{1}{3}-\frac{9}{20}\\\\=\frac{360}{60}+\frac{20}{60}-\frac{27}{60}\\\\=\frac{353}{60}\\\\=5\frac{53}{60}\\\\


lordfernand: valeu
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