Question

(1-2*cos²x)(4*sen²x-3)=0 , no intervalo [0,2π]

Answer 1

Resposta:

(1 - 2cos² x)(4sen² x - 3) = 0

1 - 2cos² x = 0

-2cos² x = -1

2cos² x = 1

cos² x = ½

cos x = ±√½

cos x = ±√(2/2)

x' = 45°

x" = 135°

x''' = 225°

x'''' = 315°

4sen² x - 3 = 0

4sen² x = 3

sen² x = ¾

sen x = ±√(¾)

sen x = ±√3/2

x' = 60°

x'' = 150°

x''' = 240°

x'''' = 330°