Question

[-1+(2^2-5×6)]÷(-5+2)+1

Answer 1

$[-1+(2^2-5*6)]:(-5+2)+1$

$[-1+(4-30)]:-3+1$

$[-1+(-26)]:-3+1$

$[-1-26]:-3+1$

$-27:-3+1$

$9+1$

$10$