Matemática, perguntado por nicolasdonascimento1, 6 meses atrás

[1/2-(1+1/2)].(2-2/3)=

Soluções para a tarefa

Respondido por CyberKirito
0

\boxed{\begin{array}{l}\sf\bigg[\dfrac{1}{2}-\bigg(1+\dfrac{1}{2}\bigg)\bigg]\cdot\bigg(2-\dfrac{2}{3}\bigg)\\\sf Vamos~resolver~quem~est\acute a~dentro~de~par\hat enteses:\\\sf\bigg[\dfrac{1}{2}-\bigg(\dfrac{2+1}{2}\bigg)\bigg]\cdot\bigg(\dfrac{6-2}{3}\bigg)\\\sf\bigg[\dfrac{1}{2}-\dfrac{3}{2}\bigg]\cdot\dfrac{4}{3}\\\sf\bigg[-\dfrac{2}{2}\bigg]\cdot\dfrac{4}{3}=-\dfrac{4}{3}\end{array}}

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