Matemática, perguntado por erikahfariasilv, 11 meses atrás

(1/1)-2+(1/2)2+(1/3)-2+(1/4)2+(1/5)

Soluções para a tarefa

Respondido por EinsteindoYahoo
2

Resposta:

Se for (1/1)-2+(1/2)²+(1/3)-2+(1/4)²+(1/5)

1-2+(1/4)+(1/3)-2+(1/16)+(1/5)

1-2+1/4+1/3-2+1/16+1/5

-3+4/16+1/3+1/16+1/5

-9/3+1/3+5/16+1/5

-8/3+25/80+16/80

-8/3+41/80  = (-8*80+3*41)/240 =-517/240

Respondido por SemDados
1

(1/1)-2+(1/2)^2+(1/3)-2+(1/4)^2+(1/5)

1−2 + 1/2^2 +1/3 −2+ (1/4)^2 +1/5

1-2+ 1/4 + 1/3 -2 + 1/16 + 1/5

- 517/240

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