Question

09. Calcule.
a) sen 8400
b) cos 23100
c) tg 41/4

Answer 1

Resposta:

a) sen 8400

8400/360= 23,3333...

pegue a parte inteira=23

8400-23*360=120

sen(120)=sen(60+60)=2*sen(60)*cos(60)=2*(√3/2)*(1/2)

sen(8400)=sen(120)=√3/2

b) cos 23100

23100/360=64,1666...

23100-64*360=60

sen(23100)=sen(60)=√3/2

c) tg 41*pi/4 = tg 41*180/4 =tg 1845

1845/360=5,125

1845-5*360 = 45

tg 41*pi/4 =tg 45= 1