Question

07) Qual o polinômio de segundo grau em que P(0) = 6, P(2) = 0 e P(1) = 2? *

P(x) = x² - 5x + 6

P(x) = x² + 5x + 6

P(x) = x² - 5x - 6

P(x) = -x² + 6

P(x) = x² + 5x - 6
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Answer 1

Resposta:

p(x)=x^2-5x+6

p(0)=0^2-5*0+6

p(0)=0-0+6

p(0)=6

idem p(x)=x^2+5x+6

p(0)=6

p(2)=0

p(x)=x^2-5x+6

p(2)=2^2-5*2+6

p(2)=4-10+6

p(2)=10-10

p(2)=0

p(1)=2

p(x)=x^2-5x+6

p(1)=1^2-5*1+6

p(1)=1-5+6

p(1)=7-5

p(1)=2