Question

03- Simplifique::

D) -3^-2

E) 3^-1+2^-1

F) 4^-2-4^-1

Answer 1

Olá ! 

Temos a regra para os expoentes : 


$x^{-y}= \frac{1}{x^{y}}$


Assim teremos: 

$-3^{-2}=- (\frac{1}{3} )^{2}=- \frac{1^{2}}{3^{2}} =\boxed{- \frac{1}{9} }$


$3^{-1}+2^{-1}=( \frac{1}{3} )^{1}+( \frac{1}{2} )^{1}= \frac{1^{1}}{3^{1}} + \frac{1^{1}}{2^{1}} = \frac{2}{6} + \frac{3}{6} =\boxed{ \frac{5}{6} }$


$4^{-2}-4^{-1}=( \frac{1}{4} )^{2}-( \frac{1}{4} )^{1}= \frac{1^{2}}{4^{2}} - \frac{1^{1}}{4^{1}} = \frac{1}{16} - \frac{1}{4} = \frac{1-4}{16} =\boxed{- \frac{3}{16} }$



Qualquer dúvida, comente! :)                                                      ok