Question

02) Resolva as equações incompletas abaixo:
a)x - 4x = 0
6) 3x + 5x = 0
c)8x - 6.x² - 0
d) 3x² + 5x = 0
e)6x - 7x = 0
12x + 6x = 0
8) 4x - 3x² = 0
h)5x – 2x=0
ix-10x=0
3x²9x=
k) 12x– 2x² = 0​

Answer 1

Explicação passo-a-passo:

$a) \: x - 4x = 0 \\ - 3x = 0 \\ - x = \frac{0}{3} \: \: \: \times ( - 1) \\ x = 0$

$b) \: 3x + 5x = 0 \\ 8x = 0 \\ x = \frac{0}{8} \\ x = 0$

$c) \: 8x - {6x}^{2} = 0 \\ x \times (8x - {6x}^{2}) = 0 \\ 8 - 6x = 0 \\ - 6x = - 8 \: \: \: \times ( - 1) \\ 6x = 8 \\ x = \frac{8}{6} \: \: \: simplificar \: \: por \: \: 2 \\ x = \frac{8 \div 2}{6 \div 2} \\ x = \frac{4}{3}$

$d) \: {3x}^{2} + 5x = 0 \\ x \times (3 {x}^{2} + 5x ) = 0 \\ 3x + 5 = 0 \\ 3x = - 5 \\ x = - \frac{5}{3}$

$e) \: 6x - 7x = 0 \\ - x = 0 \: \: \: \times ( - 1) \\ x = 0$

$f) \: 12x + 6x = 0 \\ 18x = 0 \\ x = \frac{0}{18} \\ x = 0$

$g) \: 4x - {3x}^{2} = 0 \\ x \times (4x - {3x}^{2} ) = 0 \\ 4 - 3x = 0 \\ - 3x = - 4 \: \: \: \times ( - 1) \\ 3x = 4 \\ x = \frac{4}{3}$

$h) \: 5x - 2x = 0 \\ 3x = 0 \\ x = \frac{0}{3} \\ x = 0$

$i) \: x - 10x = 0 \\ - 9x = 0 \: \: \: \times ( - 1) \\ 9x = 0 \\ x = \frac{0}{9} \\ x = 0$

$j) \: {3x}^{2} + 9x = 0 \\ x \times (3 {x}^{2} + 9x) = 0 \\ 3x + 9 = 0 \\ 3x = - 9 \\ x = - \frac{9}{3} \\ x = - 3$

$k) \: 12x - {2x}^{2} = 0 \\ x \times (12x - {2x}^{2}) = 0 \\ 12 - 2x = 0 \\ - 2x = - 12 \: \: \: \times ( - 1) \\ 2x = 12 \\ x = \frac{12}{2} \\ x = 6$