02. Calcule a raiz ou a raiz das seguintes equações, sendo U = ℚ
a) 2. ( x + 3 ) = - 28
b) 4. ( x – 2 ) = 2 . ( x + 1 )
c) 8 + 2 . ( x + 5 ) = 5
d) 2 . (5 y + 1 ) = 27
e) 2 . ( y – 1) – 1 = - 8
f) 6 . ( y + 3 ) – 2 ( y – 5 ) = 20
Soluções para a tarefa
a) 2 . (x + 3) = - 28
2x + 6 = - 28
2x = - 28 - 6
2x = - 34
x = - 34
-----
2
x = - 17
b) 4 . (x - 2) = 2 . (x + 1)
4x - 8 = 2x + 2
4x - 2x = 2 + 8
2x = 10
x = 10
---
2
x = 5
c) 8 + 2 . (x + 5) = 5
8 + 2x + 10 = 5
2x = 5 - 8 - 10
2x = 5 - 18
2x = - 13
x = - 13
--- ou -6,5
2
d) 2 . (5y + 1) = 27
10y + 2 = 27
10y = 27 - 2
10y = 25
y = 25
-----
10
y = 2,5
e) 2 . (y - 1) - 1 = - 8
2y - 2 - 1 = - 8
2y = - 8 + 2 + 1
2y = - 8 + 3
2y = - 5
y = - 5
--- ou - 2,5
2
f) 6 . (y + 3) - 2(y - 5) = 20
6y + 18 - 2y + 10 = 20
6y - 2y = 20 - 18 - 10
4y = 20 - 28
4y = - 8
y = - 8
---
4
y = - 2
a) 2. ( x + 3 ) = - 28
2x+6 = -28
2x = -28-6
2x = -34
x = -34/2
x = -17
b) 4. ( x – 2 ) = 2 . ( x + 1 )
4x-8 = 2x+2
4x-2x = 2+8
2x = 10
x = 10/2
x = 5
c) 8 + 2 . ( x + 5 ) = 5
8+2x+10 = 5
2x = 5-8-10
2x = -13
x = -13/2
d) 2 . (5 y + 1 ) = 27
10y+2 = 27
10y = 27-2
10y = 25
y = 25/10
y = 5/2
e) 2 . ( y – 1) – 1 = - 8
2y-2 -1 = -8
2y = -8+2+1
2y = -8+3
2y = -5
y = -5/2
f) 6 . ( y + 3 ) – 2 ( y – 5 ) = 20
6y+18-2y+10 = 20
4y = 20-18-10
4y = 20-28
4y = -8
y = -8/4
y = -2
Boa noite ❤️
12/10/21
