Question

01) O valor de (3 √3i^15 +i^16 +i^2 )^2 é:
a)9i
b)–9
c)27i
d)–27
e)–i

Answer 1

(3 i^3+i^0+i^2)^2 ...... (i^2= -1 .... i^3= i^2 . i=-i )

(3i+1-1)^2=

(3i)^2= 3².i²=-9