Matemática, perguntado por eduumaria2007, 8 meses atrás

01) Determine a solução das sequências do do 1 grau, abaixo:


A) 4. (×-2)-2. (×+1)=4
B) 10+(×-2)=5-2. (×+4)
C) 10. (×+1)-6=2. (×-3)-10
D) X/2 - X/5 =21
E) 2×/5 -2=X/4+4
F) X- X/3=6+X/2​

Soluções para a tarefa

Respondido por xanddypedagogoowelwo
1

Respostas:

Vamos lá!

A) 4. (×-2)-2. (×+1)=4

4x - 8 - 2x - 2 = 4

2x = 4 + 10

x = 14/2

x = 7

B) 10+(×-2)=5-2. (×+4)

10 + x - 2 = 5 - 2x - 8

x + 2x = - 3 - 8

3x = - 11

x=-\dfrac{11}{3}\\

C) 10. (×+1)-6=2. (×-3)-10

10x + 10 - 6 = 2x - 6 - 10

10x - 2x = - 16 - 4

8x = - 20

x=-\dfrac{20}{8} \\\\x=-\dfrac{5}{2}

D) X/2 - X/5 =21

\dfrac{5x-2x}{10} =21\\\\\dfrac{3x}{10} =21\\\\3x=210\\\\x=210/3\\\\x =70

E) 2×/5 -2=X/4+4

\dfrac{2x}{5} -2=\dfrac{x}{4} +4\\\\\dfrac{8x-40}{20} =\dfrac{5x-80}{20} \\\\8x-40=5x-80\\\\8x - 5x=-80+40\\\\3x=-40\\\\x=-\dfrac{40}{3}

F) X- X/3=6+X/2​

x-\dfrac{x}{3} =6+\dfrac{x}{2} \\\\\\\dfrac{6x-2x}{6} =\dfrac{36+3x}{6} \\\\\\6x-2x=36+3x\\\\4x-3x=36\\\\x=36\\

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