Matemática, perguntado por elprofessor49, 7 meses atrás

01. Calcule os quadrados:
a) (3x + 1)2 =
c) ( 23 - 3c)2 =
b) (x10+ 4 )2 =
d) (5a - 3)2 =
02. Simplifique as expressões:
a) (x+1)++ (x+ 5)2 =
c) ( 3x - 1)2 + (x - 2)2 =
b) (x+y)2 -2C x2 + y2 ) =
d) (1 - 2x)2 - (1 + x)2 =
e) (x+3)(x-3)+(x - 3)2 =
03. Calcule os produtos:
a) (x+9). (x - 9) =
b) (xy + 4). (xy - 4) =
c) ( 5x2 - y2) ( 5x2 - y2) =​

Soluções para a tarefa

Respondido por edivaldocardoso
1

Resposta:

01)

a)

(a + b) {}^{2} =  {a}^{2}  + 2ab +  {b}^{2}   \\  \\ (3x + 1) {}^{2}  = (3x) {}^{2}  + 2(3x)(1) +  {(1)}^{2}  \\  \\  = \Large \boxed{ \green{ 9 {x}^{2}  + 6x + 1}}

c)

(a - b) {}^{2} =  {a}^{2} - 2ab +  {b}^{2}    \\  \\ (23 - 3c) {}^{2}  =  {(23)}^{2}  - 2(23)(3c) +  {(3c)}^{2}  \\  \\  =  \Large \boxed{ \green{529 - 138c + 9 {c}^{2} }}

b)

 ({x}^{10}  + 4) {}^{2}  =(  {x}^{10})  {}^{2}  + 2( {x}^{10} )(4) +  {4}^{2}  \\  \\  = \Large \boxed{  \green{ {x}^{20}  + 8 {x}^{10}  + 16}}

d)

(5a - 3) {}^{2}  = (5a) {}^{2}  - 2(5a)(3) +  {3}^{2}  \\  \\  = \Large \boxed{ \green{ 25 {a}^{2}  - 30a + 9}}

02)

a)

(x + 1) + (x + 5) {}^{2}  =  \\  \\  = x + 1 +  {x}^{2}  + 2(x)(5) +  {5}^{2}  \\  \\  = x + 1 +  {x}^{2}  + 10x + 25 \\  \\  =  \Large \boxed{ \green{ {x}^{2}  + 11x + 26}}

c)

(3x - 1) {}^{2}   + (x - 2) {}^{2}  =  \\  \\ =  (3x) {}^{2}  - 2(3x)(1) +  {1}^{2}  +  {x}^{2}  - 2(x)(2) +  {2}^{2}  \\  \\  = 9 {x}^{2}  - 6x + 1 +  {x}^{2}  - 4x + 4 \\  \\  =  \Large \boxed{ \green{10 {x}^{2}  - 10x + 5}}

b)

(x + y) {}^{2}  - 2( {x}^{2}  +  {y}^{2} ) =  \\  \\  =  {x}^{2}  + 2xy +  {y}^{2}  - 2 {x}^{2}  - 2 {y}^{2}  \\  \\  =  \Large \boxed{ \green{ -  {x}^{2}   + 2xy -  {y}^{2} }}

d)

(1 - 2x) {}^{2}  - (1 + x) {}^{2}  =  \\  \\ =   {1}^{2}  - 2(1)(2x) + ( {2x)}^{2}  - ( 1 + 2x +  {x}^{2} ) \\  \\ \red 1 - 4x + 4 {x}^{2} \red{  - 1} - 2x -  {x}^{2}  \\  \\  =   \Large \boxed{ \green{- 3 {x}^{2}  - 6x}}

e)

 (x + 3)(x - 3) + (x - 3) {}^{2}  =  \\  \\   = {x}^{2}  - (3) {}^{2}  +  {x}^{2}  - 2(x)(3) +  {3}^{2}  \\  \\  =  {x}^{2} \red{  - 9} +  {x}^{2}  - 6x \red{ + 9 }\\ \\   =  \Large \boxed{ \green{2 {x}^{2}  - 6x}}

3)

a)

(x + 9)(x - 9) =  {x}^{2}  -  {9}^{2}  =  \\  \\  =  \Large \boxed{ \green{ {x}^{2}  - 81}}

b)

(xy + 4)(xy - 4) =  \\  \\ (xy) {}^{2}  -  {4}^{2}  =  \\  \\  =  \Large \boxed{ \green{ {x}^{2}  {y}^{2}   - 16}}

c)

(5 {x}^{2}  -  {y}^{2} )(5 {x}^{2}  -  {y}^{2} ) =  \\  \\ (5 {x}^{2} ) {}^{2}  - ( {y}^{2} ) {}^{2}  =  \\  \\  =   \Large\boxed{ \green{5 {x}^{4}  -  {y}^{4} }} \\  \\  \Large \boxed{ \underline{ \blue{ \bf \: Bons \: Esudos!}11/05/2021}}

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