Question

01- Calcule:

D) [1/4*(-2/3)-(5/6)]^2÷(3/2)^-1=

E) (-2/3)^2*(3/4)+1/4=

F) 3*10^-6*6*10
------------------------
9*10^-8

Answer 1

Olá !

Vamos resolver as equações ....

[1/4 . (-2/3) - (5/6)]^2 : (3/2)^-1

[-2/12 - 5/6]^2 : 2/3^1

[-1/6 - 5/6]^2 : 2/3

[-6/6]^2 : 2/3

[ -1 ]^2 : 2/3

1 : 2/3

1/1 . 3/2 = 3/2

==============================================

(-2/3)^2 . 3/4 + 1/4

4/9 . 3/4 + 1/4

12/36 + 1/4

1/3 + 1/4

4/12 + 3/12 = 7/12

=======================================

[3.10^-6 . 6 . 10]/[9.10^-8]

[3.6.10^-6.10]/[9.10^-8]

[18.10^-5]/[9.10^-8]

18/9 . 10^-5/10^-8

2 . 10^(-5 - (-8))

2 . 10^(-5 + 8)

2 . 10^3

2. 1000 = 2 000 ok