Question

0 valor de sen 1590ᵒ é * 1 ponto a) -1/2 b) 0 c) -1 d) 1/2

Answer 1

$\mathsf{1590^{\circ}=4\times360^{\circ}+150^{\circ}}\\\mathsf{sen(1590^{\circ}) =sen(150^{\circ}) =sen(30^{\circ})=\dfrac{1}{2}}$