Question

0 numero complexos z=5 +yi tal q z+(3+2i)= ´z+(3+10i)

Answer 1

z=5 +yi
 z+(3+2i)= ´z+(3+10i)
'z=conjugado

5+yi+3+2i=5-yi+3+10i

2yi=10-2i
y.2i=8i
y=8i/2i
y=4

Z=5+4i