Question

∫_0^5 (3t² + 30t + 36)

Answer 1

Resposta:$\int _0^53t^2+30t+36dt=680$

Explicação passo a passo:

$\mathrm{Aplicar\:a\:regra\:da\:soma}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=\int _0^53t^2dt+\int _0^530tdt+\int _0^536dt\\=\int _0^53t^2dt=125$

$=\int _0^530t^2dt=375\\=\int _0^536t^2dt=180\\=125+375+180=680$

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