0,25²×+³=4×+¹
porfavor manda resposta
Anexos:
![](https://pt-static.z-dn.net/files/d9b/ab49008bb8715bbdfe25ac77ca862833.jpg)
cleomarelite:
aee alguém sabe
Soluções para a tarefa
Respondido por
0
A = (0,25) -² - (0,5)-³ + (0,125)-¹
A = (25/100)⁻² - (5/10)⁻³ + (125/1000)⁻¹
A = (100/25)² - (10/5)³ + (1000/125)¹
A = (4)² - (2)³ + 8
A = 16 -8 +8
A= 16
quando o gabarito não bate com a resposta,
entra o grande nerd( a cpu), como juiz, para desempatar.
A=(0.25)^(-2) - (0.5)^(-3) + (0.125)^(-1)
A = <16.00000000>
A = (25/100)⁻² - (5/10)⁻³ + (125/1000)⁻¹
A = (100/25)² - (10/5)³ + (1000/125)¹
A = (4)² - (2)³ + 8
A = 16 -8 +8
A= 16
quando o gabarito não bate com a resposta,
entra o grande nerd( a cpu), como juiz, para desempatar.
A=(0.25)^(-2) - (0.5)^(-3) + (0.125)^(-1)
A = <16.00000000>
Respondido por
1
Olá Cleo,
aplique as propriedades da potenciação:
![(0,25)^{2x+3}=4^{x+1}\\\\
( \dfrac{1}{4})^{2x+3}=4^{x+1}\\\\
(4^{-1})^{2x+3}=4^{x+1}\\\\
\not4^{-2x-3}=\not4^{x+1}\\\\
-2x-3=x+1\\
-2x-x=1+3\\
-3x=4\\\\
x=-\dfrac{4}{3}\\\\
\boxed{S=\{- \dfrac{4}{3}\}} (0,25)^{2x+3}=4^{x+1}\\\\
( \dfrac{1}{4})^{2x+3}=4^{x+1}\\\\
(4^{-1})^{2x+3}=4^{x+1}\\\\
\not4^{-2x-3}=\not4^{x+1}\\\\
-2x-3=x+1\\
-2x-x=1+3\\
-3x=4\\\\
x=-\dfrac{4}{3}\\\\
\boxed{S=\{- \dfrac{4}{3}\}}](https://tex.z-dn.net/?f=%280%2C25%29%5E%7B2x%2B3%7D%3D4%5E%7Bx%2B1%7D%5C%5C%5C%5C%0A%28+%5Cdfrac%7B1%7D%7B4%7D%29%5E%7B2x%2B3%7D%3D4%5E%7Bx%2B1%7D%5C%5C%5C%5C%0A%284%5E%7B-1%7D%29%5E%7B2x%2B3%7D%3D4%5E%7Bx%2B1%7D%5C%5C%5C%5C%0A%5Cnot4%5E%7B-2x-3%7D%3D%5Cnot4%5E%7Bx%2B1%7D%5C%5C%5C%5C%0A-2x-3%3Dx%2B1%5C%5C%0A-2x-x%3D1%2B3%5C%5C%0A-3x%3D4%5C%5C%5C%5C%0Ax%3D-%5Cdfrac%7B4%7D%7B3%7D%5C%5C%5C%5C%0A%5Cboxed%7BS%3D%5C%7B-+%5Cdfrac%7B4%7D%7B3%7D%5C%7D%7D++++++++++)
____________________________
![\sqrt[6]{1.000}*10^x=0,001\\\\
\sqrt[6]{10^3}*10^x= \dfrac{1}{1000}\\\\\\
10^{ \tfrac{3}{6} }*10^x= \dfrac{1}{10^3}\\\\\\
10^{ \tfrac{1}{2} }*10^x=10^{-3}\\\\
\not10^{ \tfrac{1}{2}+x }=\not10^{-3} \\\\
\dfrac{1}{2}+x=-3\\\\
1+2*x=2*(-3)\\
1+2x=-6\\
2x=-6-1\\
2x=-7\\\\
x=- \dfrac{7}{2}\\\\
\boxed{S=\{-\dfrac{7}{2}\}} \sqrt[6]{1.000}*10^x=0,001\\\\
\sqrt[6]{10^3}*10^x= \dfrac{1}{1000}\\\\\\
10^{ \tfrac{3}{6} }*10^x= \dfrac{1}{10^3}\\\\\\
10^{ \tfrac{1}{2} }*10^x=10^{-3}\\\\
\not10^{ \tfrac{1}{2}+x }=\not10^{-3} \\\\
\dfrac{1}{2}+x=-3\\\\
1+2*x=2*(-3)\\
1+2x=-6\\
2x=-6-1\\
2x=-7\\\\
x=- \dfrac{7}{2}\\\\
\boxed{S=\{-\dfrac{7}{2}\}}](https://tex.z-dn.net/?f=+%5Csqrt%5B6%5D%7B1.000%7D%2A10%5Ex%3D0%2C001%5C%5C%5C%5C%0A+%5Csqrt%5B6%5D%7B10%5E3%7D%2A10%5Ex%3D+%5Cdfrac%7B1%7D%7B1000%7D%5C%5C%5C%5C%5C%5C%0A10%5E%7B+%5Ctfrac%7B3%7D%7B6%7D+%7D%2A10%5Ex%3D+%5Cdfrac%7B1%7D%7B10%5E3%7D%5C%5C%5C%5C%5C%5C%0A10%5E%7B+%5Ctfrac%7B1%7D%7B2%7D+%7D%2A10%5Ex%3D10%5E%7B-3%7D%5C%5C%5C%5C%0A%5Cnot10%5E%7B+%5Ctfrac%7B1%7D%7B2%7D%2Bx+%7D%3D%5Cnot10%5E%7B-3%7D+%5C%5C%5C%5C%0A+%5Cdfrac%7B1%7D%7B2%7D%2Bx%3D-3%5C%5C%5C%5C%0A1%2B2%2Ax%3D2%2A%28-3%29%5C%5C%0A1%2B2x%3D-6%5C%5C%0A2x%3D-6-1%5C%5C%0A2x%3D-7%5C%5C%5C%5C%0Ax%3D-+%5Cdfrac%7B7%7D%7B2%7D%5C%5C%5C%5C%0A%5Cboxed%7BS%3D%5C%7B-%5Cdfrac%7B7%7D%7B2%7D%5C%7D%7D+++++++++++)
Espero ter ajudado e tenha ótimos estudos =))
aplique as propriedades da potenciação:
____________________________
Espero ter ajudado e tenha ótimos estudos =))
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